17-0.20x=x^2

Solution for 17-0.20x=x^2 equation:

17-0.20x=x^2

We move all terms to the left:

17-0.20x-(x^2)=0

determiningTheFunctionDomain
-x^2-0.20x+17=0

We add all the numbers together, and all the variables

-1x^2-0.2x+17=0

a = -1; b = -0.2; c = +17;
Δ = b2-4ac
Δ = -0.22-4·(-1)·17
Δ = 68.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.2)-\sqrt{68.04}}{2*-1}=\frac{0.2-\sqrt{68.04}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.2)+\sqrt{68.04}}{2*-1}=\frac{0.2+\sqrt{68.04}}{-2}
$